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Tag Archive for ‘Dr. FAE’

The Joys of Superposition – Part One

September 29, 2011

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By Dr. F.A.E.

Dear Dr. Engleberry, I have to analyze the control loop of a circuit that uses your voltage-mode FAN1577A switching regulator, but the complex equations are overwhelming. I like the part with its built-in FET drivers, but the equations? Not so much.

Anxious in Allentown

Dear Anxious. One thing to keep in mind is that the equations are a tool for describing circuit operation and often the circuit value you must derive can be generated with a much less complex formula scribbled on a napkin, pre-digested in a spreadsheet or from a computer model created by someone else. The fact is, there are many ways to understand circuit operation and, as long as the final design meets the requirements, it does not matter which path was taken.

If it is any consolation, some of the great pioneers of electronics felt inadequate when looking at the mathematical representations. Take Michael Faraday for example. He was much more comfortable measuring and documenting the results of his experiments. He was very uncomfortable with the folks who came later and described physics with formulas. After all what is a formula? It does not define nature. The formula is a mental tool which should help us understand the underlying linkages between cause and effect, but no formula is perfect and if it doesn’t shed light? Then throw it out!

One ray of hope I can offer is superposition. Superposition tells us that the behavior of a circuit can be described by analyzing all the individual signals in isolation, then summing the results all together. We don’t have to choke down the whole circuit all at once…we can chop it up into as many pieces as we like and ingest them one-by-one.

However, I don’t want to mislead you. The complexity can still be overwhelming. Let’s start Part 1 of our superposition exercise with the output capacitor you might find in a power supply output.

Courtesy of our friends at Nippon Chemi-Con, I grabbed an 820uF capacitor off my bench. The device says 820uF, so am I safe to use that value in my transfer function? I plugged one into my LCR meter and here’s what I see:

Frequency   Capacitance   ESR

100Khz         -428uF            6.95mOhm

10Khz            745uF            9.5mOhms

1Khz              774uF           12.9mOhm

100Hz           788uF            33mOhm

The datasheet says this is a 820uF, 7 mOhm capacitor with plus and minus 20% initial tolerance. -428uF? What does that mean? It means this component is not a capacitor at 100Khz-its an inductor–and the crossover point (self-resonant frequency where C=L) is somewhere between 10Khz and 100Khz.

So, what do I conclude from this? Via superposition, it’s okay to analyze the operation of this capacitor all on its own…then sum it into the larger circuit. But, if you want to accurately understand the bigger picture, you have to take into account the actual component properties with the signals and conditions it will actually see in your circuit.

We will continue this discussion in The Joys of Superposition, Part 2.

Can we have a brief moment of silence to honor Jim Williams and Bob Pease? The loss of these two giants of the analog design world is immense. We have no choice…though we can’t begin to fill their shoes…we must carry on.

RIP, Jim and Bob.

References:

FAN1577 A http://www.fairchildsemi.com/pf/FA/FAN1577A.html

The Electric Life of Michael Faraday, Alan Hirshfeld, Walker & Company, 2006


About the author:
Dr. Fred A. Engleberry (also know as Dr. F.A.E.) holds a PhD from MIT (Muckton Institute of Talknology). Fred has a world-class intellect and rarely neglects an opportunity to mention it. Argumentative and contentious, he's often irritatingly correct when answering questions and discussing semiconductor technology, real world design trade-offs and engineering issues. Dr. F.A.E's core competencies include using big words when small ones would suffice and providing long-winded, indirect answers to simple questions.

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How do you stabilize an unruly boost converter?

March 25, 2011

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By Dr. F.A.E.

drfae_iconDear Fred. Can I call you Fred? I hope so. Can you help me? I am trying to stabilize a boost converter, but it reminds me of my three-year-old daughter. She won’t behave. Neither will my boost regulator. I know you like design details. My converter is running with a 100Khz clock. Vin is 12V and Vout is 60V. The output current rating is 100mA. I’m using a 10uH inductor.

 

PS: My daughter is named Fred too. I named her after you. I am your biggest fan.

 

Unruly in Redmond

 

Dear Unruly. I prefer to be addressed as Dr. Engleberry. I ask everyone, even my dear mother who turns 104 next month, to call me Dr. Engleberry. She stubbornly refuses, though I have reminded her 1753 times (yes, I keep track of this sort of thing). You can only imagine how aggravating that is. It steams my cappuccino.

 

With regard to your boost converter…these designs can be tricky, particularly when the inductor current is continuous and the duty cycle is greater than 50%. Let’s take a look and see where you are.

 

The clock period is 10µSec.  can be calculated with the following formula:

dr-fae_9_ton

 Where:   

dr-fae_9_tp1This gives:    

dr-fae_9_ton1

As I feared, we are running into a problem called the RHP Zero. RHP stands for Right-Half Plane. This sounds complex, but the idea is simple enough. The inductor is ‘charged’ for 8µSec and discharged for 2µSec. As long as the load is stable, everything runs fine, but let’s imagine a fast increase in load current is demanded. The only way to get more power out of the inductor is to put more into it. How do we put more in? With a longer on-period, of course. But, with a fixed-frequency converter, the larger on-period comes at the expense of the off period. With a shorter off-period, we get less output power.

 

That’s right. We want more output power, but until we establish a new operating point for the inductor, we get less output power. This problem is characteristic of the boost converter and with these operating conditions, there is nothing we can do. The real problem comes when we try to compensate this power supply. If we have too fast of a responses time, then the converter will try to compensate for the reduced output voltage and we’ll see horrible overshoot and undershoot and even worse, instability in the control loop. So, we must roll off the response loop at a much lower frequency than we’d like to see.

 

What can we do? Abandon the boost converter topology and use a flyback converter?

 

PS: This is an odd coincidence, but my mother’s name is Fred too.

 

=========================

You can read more about boost converters in these technical articles:

Building Variable Output Voltage Boost PFC Converters with the FAN9612 Interleaved BCM PFC Controller.

UniFETTM - Optimized Switch for Discontinuous Current Mode Power Factor Correction.

 

Specific products related to this are:

FAN5333A   

FAN5340

FAN9612


About the author:
Dr. Fred A. Engleberry (also know as Dr. F.A.E.) holds a PhD from MIT (Muckton Institute of Talknology). Fred has a world-class intellect and rarely neglects an opportunity to mention it. Argumentative and contentious, he's often irritatingly correct when answering questions and discussing semiconductor technology, real world design trade-offs and engineering issues. Dr. F.A.E's core competencies include using big words when small ones would suffice and providing long-winded, indirect answers to simple questions.

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Adventures in Optocoupling

February 24, 2011

- 2 Comments
By Dr. F.A.E.

drfae_iconDear Dr. FAE. You’re always going on and on (and on) about how smart you are…perhaps you’d like a challenge where I give you the answer-and you have to figure out the question. Here’s the answer: a 1150 ohm resistor. You don’t feel so smart now, do you, Dr. Smartypants?

  • - Throwing Down in Tampa

Through the application of only a small portion of my intellect, I can tell your question relates to selecting the right pull-up resistor to use for a cost-effective, low-performance optocoupler circuit…to be specific, the half-pitch, mini-flat packaged HMHA281 device. This is a simple circuit, but there are still a few things to consider when designing a reliable and robust detection circuit.

dr-fae_opto_2_11

 

First of all, we need to select a current-limiting resistor for the emitter circuit. With a 12Vin, a forward voltage drop of 1.3V across the LED and a reasonable current of 8mA, let’s figure out what value of resistor should be used…

dr-fae_opto2_2_111 

The closest standard value is 1.33K, so we’ll use that.

We’re using a standard CMOS logic gate (with hysteresis) as a detector on the secondary side. The question is, with the optocoupler turned on, what voltage do we need to provide to make sure the gate input detects a logic zero? So, we look at the NC7SZ14 datasheet. In order to be recognized as a logic zero over a wide operating temperature range, the input voltage must be less than 1.30V.

How do we guarantee a voltage no greater than 1.30V when the detector transistor is on? We’re running this device in a switch mode, so we need to know the minimum Current Transfer Ratio (CTR) with a saturated detector transistor. This is not something that can be read directly off the datasheet but we can derive it from the VCE(SAT) transfer characteristic in the HMHA281 datasheet. With an IF of 8mA, we get an IC of 2.4mA; that gives us a CTR of 2.4/8 or 30%. This is a typical minimum at room temperature, so we need to derate it for temperature. By studying Figure 4 of the HMHA281 datasheet, we see that we need about an 80% derating at 55°C, so that gives us a minimum CTR of about 24%.

Being clever and highly experienced, we know that a gently-treated optocoupler’s CTR will degrade by about 1% per year. If we expect this design to work for ten years, then we should derate the CTR an additional 10%…to 21.6%.

By gently-treated, we mean the optocoupler is not exposed to high ambient temperatures, large emitter/detector currents or extreme thermal cycling. With more aggressive environments and usage, we can expect degradation closer to 2% per year.

With 8mA emitted, then the minimum current in the output phototransistor is:

dr-fae_opto3_2_11

So, what pull-up resistor value do we need to make sure the voltage at the inverter input is less than 1.30V when 1.73mA flows through it?

dr-fae_opto4_2_11 

We’ll choose 1150 ohms as the closest standard value. Pardon me while I do a little victory waltz. 1150 ohms. Boom, I have dispensed with your challenge.

I don’t anticipate any problems, but we should make sure the ‘off’ current will be detected as a logic ‘one’. According to Figure 8 of the HMHA281 datasheet, we can expect 10uA of dark current at 55°C. This will drop 11.6mV across the pull-up resistor. The resulting voltage at the gate input is much more than 2.2V required to assure a logic ‘one’ is detected. So, all is well.

This was a lot of work to create a low-speed logic interface. If you want us to the hard work, you can use a device with the logic detection built in, like the FODM8061.

There - that is the question to your answer - and yes I do feel smart!

 Let me throw a challenge back at you, TDiT…and to my readers around the world. Here’s the answer: Valvular Conduit. What is the question?

The first right answer in the comment section below will win a trendy and fashionable prize package, including my attractive and collectable signed photograph and a 2N7002 transistor.

 Sincerely, Dr. FAE aka “Smartypants”


About the author:
Dr. Fred A. Engleberry (also know as Dr. F.A.E.) holds a PhD from MIT (Muckton Institute of Talknology). Fred has a world-class intellect and rarely neglects an opportunity to mention it. Argumentative and contentious, he's often irritatingly correct when answering questions and discussing semiconductor technology, real world design trade-offs and engineering issues. Dr. F.A.E's core competencies include using big words when small ones would suffice and providing long-winded, indirect answers to simple questions.

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Reliable Reliability

July 20, 2010

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By Dr. F.A.E.

 drfae_icon With an IQ of 181, you might think it’s hard for me to amuse myself, but it’s not true. I like a little light reading in the evening…things like Kreck and Lück’s The Novikov Conjecture (A group G is a-T-menable, or, equivalently, has the Haagerup property if G admits a metrically proper isometric action on some affine Hilbert space, page 205) or Carver Mead’s Collective Electrodynamics (Because the system spatial attributes of the system in an eigenstate are stationary, the system in an eigenstate cannot radiate energy, page 106.)

 Fascinating, riveting stuff, I’m sure you agree.

 This led me to think a little bit about semiconductor reliability, though I confess my thinking might have been influenced by the consumption of a bottle of Puligny Montrachet Grand Cru Domaine des Comtes Lafon. In case you’re unfamiliar, that’s a wine very similar in appearance to the Franzia Crisp White wine you can buy in a box at the local market.

 I mentioned Carver Mead above. Among his many accomplishments, he was the guy who contributed to Moore’s Law (which says transistor density on an integrated circuit will approximately double every two years) when Gordon Moore worked at Fairchild Semiconductor in the 1960s.

 In 1965, Gordon had just started making his plots, where he’d plot the logarithm of the number of transistors on a chip as a function of the year. They’re little hand-drawn plots. I still have some around. One day we were talking about his plots. He said “You’re working on electron tunneling that happens when things get really small, right?” Yeah. “Well, wouldn’t that limit how small you can make a transistor?” Yes. “Well, how small is that?” Gordon has a way of asking these very simple questions that you really think you should know the answer to, and I didn’t. I said, well, I have to go and think about it. I’ve been thinking about it ever since. Carver Mead, from a speech at Telecosm 2006

 The driver for Moore’s Law is the fact that as we make transistors smaller, they get cheaper to manufacture AND they work better. Isn’t that something? They work better. Think about that. And, what do we mean by working better? They consume less power and they can switch more quickly. This is the small miracle that fuels the marvelous advances of the digital revolution.

 Today Fairchild is a leader in power management and mobile technology and in our factories, over 50 years after Fairchild Semiconductor was originally formed, we continue to take advantage of the state-of-the-art in transistor lithography.

 There are not many businesses like ours where customers expect continuous improvement in products-with lower prices every year. Generally, if you buy the bargain brand at the big-box discount store, you expect lower quality…fewer features and less reliability. If you buy an inexpensive car, you expect it to be less comfortable and less reliable than a premium brand. But, that’s not how the semiconductor business works. Regardless of what you pay for our product, you expect high reliability…robust and rugged components.

 Year-by-year, we practice continuous improvement and do our part to produce parts with very low failure rates. As a semi-random example, we publish a 3.65 FIT (Failure in Time) rating for the n-channel FET NDT3055. This works out to one failure for 3,127 years of operation.

 Let’s take a closer look at what this means. We can’t build up a significantly significant number of parts and test them for 3,127 years. We’d love to, but we can’t. The FIT rating is based on accelerated testing of sample parts with numbers plugged into a formula.

 The basic idea is that by aging sample devices with high humidity and overvoltage stress, we can estimate the failure rate without waiting for tens of thousands of years.

 As I mentioned above, we do our part to create robust devices for our customers. However, is there also a role for the customer? Of course there is.

 In building up our reliability estimate, we use a temperature stress factor adapted from the Arrhenius equation-which includes this term:

 

eEa/k(1/Tu - 1/Ts)

Where:

Ea = Semiconductor activation energy

k = Boltzmann’s Constant

Tu = use temperature (K), or the die temperature in the design.

Ts = stress temperature (K) used in the accelerated life test.

 We control the stress temperature and it is based on the semiconductor process, generally either 150 degrees C (423K) or 175 degrees C (448K). You control the use temperature. Lower operating temperatures result in higher reliability. That’s your part of the job.

 So, let’s say you want to increase the reliability of a system. Using the free MTBF tool referenced at the end of this blog, we can see the predicted effect of reducing the operating temperature from 100 degrees C to 90 degrees C.

 At 100C, the calculated FIT is 1009.

At 90C, the calculated FIT is 860.

Is that enough of an improvment? That depends on your needs.

Please note I am not saying anything about the fundamental reality of these numbers. They are numbers, but there is a fair amount of speculation and unconsidered factors in a real life design.

 It’s getting late and I notice there is about a half a glass left in the bottle. I suppose I could put the cork back in and save that last bit for later.

 Or not.

 The unpublished papers referenced below are available by request.

 The author would like to thank Thomas Welch and Raymond Oakley who collectively contributed three unhelpful suggestions and two rude comments during the writing of this article.

 References

On Acceleration Factors used in Failure Rate Prediction - Unpublished paper by Thomas Welch, Director, Quality and Reliability, Fairchild Semiconductor

Secrets of Mean Time Between Failure - Unpublished paper by Raymond Oakley, Staff Customer Quality Engineer, Fairchild Semiconductor

Free MTBF tool from Advanced Logistics Developments, Free MTBF Tool

Failure Mechanisms and Models for Semiconductor Devices, JEDEC Publication, JEP122E

Reliability by Design, A. C. Brombacher, John Wiley and Sons

Reliability, Maintainability and Availability Assessment, Mitchell O. Locks, Hayden Book Company

Collective Electrodynamics, Carver A. Mead, The MIT Press

The Novikov Conjecture, Matthias Kreck and Wolfgang Lück, Birkhauser Verlag


About the author:
Dr. Fred A. Engleberry (also know as Dr. F.A.E.) holds a PhD from MIT (Muckton Institute of Talknology). Fred has a world-class intellect and rarely neglects an opportunity to mention it. Argumentative and contentious, he's often irritatingly correct when answering questions and discussing semiconductor technology, real world design trade-offs and engineering issues. Dr. F.A.E's core competencies include using big words when small ones would suffice and providing long-winded, indirect answers to simple questions.

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Would you care for an IC?

May 7, 2010

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By Dr. F.A.E.

drfae_iconInstead of answering one of the many technical questions that cross my desk, I hope you’ll indulge me while I digress to tell you about the party I attended in Manhattan last week. Perhaps you saw pictures from this gathering…it was hosted by the widow of a moderately infamous oil mogul and many of the single-name-only crowd were there: Angie and Brad, Jewel, Cher, Sting, Jen, Björk, Moby and others, as were a random collection of B-list partiers…rappers, lobbyists, literary agents, fashion models….and the ever-present John Q. Fields-you know, the ubiquitous actor with the very high IQ (but not quite so high as mine, thank you very much).

The first thing you’ll want to know is how an engineer gets an invitation to a party like this, but I can’t help you. That’s a path you’ll have to blaze on your own.

After a stare-down with the bartender who tried to insult me with an exceptionally average Cognac when, from a prior visit to this expansive apartment, I knew there was a bottle of Cognac Dudognon Héritage HENRI IV hidden in a secret storage nook behind the hallway Matisse print (Woman with a Hat, or rather, an inept counterfeit). I was minding my own business by the fireplace when a pretty TV actress planted the heel of one of her Jimmy Choo slingbacks directly on my instep. After accepting her profuse apology, we struck up a conversation and she asked what I do for a living.

“I work for a semiconductor company…a famous one with a long history of accomplishment and invention.” But it had no meaning or relevance to her. She looked at me as if I was speaking in tongues-until I explained.

“Unless you’re an electrical engineer, you might not be familiar with Fairchild Semiconductor, but it’s highly likely that you own many of our products. For example, do you own a brand name flatscreen TV? Then, most likely, you own numerous Fairchild components. Do you have a game console? The most popular ones are built with Fairchild parts. Do you drive a car with a navigation system? Do you have a cell phone with a digital still camera? Do you have a DVR? A computer? An Energy Star® air conditioner or washing machine? A printer? A music player? We’re everywhere and you are our customer! Your life is probably overflowing with hundreds of our tiny, energy-saving, feature-enhancing components. You might not know our name, but we reduce the energy consumption of your computer, provide the backlighting for your LCD TV, increase the talk time on your cell phone, and generally power your world.”

As you might imagine, she swooned-and peppered me with questions about our support for soon-to-be-released cell phone features and enhancements, which I will share later.

Then, eavesdroppers quickly spread the word. Many stopped by to shake my hand and kiss my cheek…and thank me for our contributions to their way of life…for helping to create and power all the beautiful things that enrich and enable our fabulous modern lifestyle.

Snifters of the secret stash of cognac finally came my way, but I could hardly find a quiet moment to enjoy a sip.

Oh, my friends, celebrity can be such a heavy burden.

But, have no worry.

I can handle it.

I’ll be fine.


About the author:
Dr. Fred A. Engleberry (also know as Dr. F.A.E.) holds a PhD from MIT (Muckton Institute of Talknology). Fred has a world-class intellect and rarely neglects an opportunity to mention it. Argumentative and contentious, he's often irritatingly correct when answering questions and discussing semiconductor technology, real world design trade-offs and engineering issues. Dr. F.A.E's core competencies include using big words when small ones would suffice and providing long-winded, indirect answers to simple questions.

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What’s Up with Feedback Loops?

October 23, 2009

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By Dr. F.A.E.

Greetings to Dr. FAE,
I notice many of your competitors do not use feedback loops in their reference designs. You guys have some parts with no feedback loop (like the tiny 0.6A 6MHz FAN5361 regulator http://www.fairchildsemi.com/pf/FA/FAN5361.html) while some parts, like your new 4A integrated regulator FAN21SV04 (http://www.fairchildsemi.com/pf/FA/FAN21SV04.html) do have an external feedback loop. I wonder: why is this? If I have a choice, I don’t want to mess around with external parts and complicated circuit analysis. It would make my life easier if you’d quit making parts with feedback loops.  - - - Baffled in Buffalo

Dear Mister Baffled,

If we’re talking about making people’s lives easier, you could connect our parts to well-behaved loads with well-behaved sources and we could sell you expensive resistors in fancy packages and make a lot of money.

However, most parts that provide a regulated output have a feedback loop for control and enhanced stability. Sometimes this feedback loop is buried inside the part…in that case we design a control loop we think will work well for a variety of circuits a customer might hook it to. Even a simple device like a Low-Dropout (LDO) regulator has a feedback loop from the output to control the conduction of the pass transistor. This is why, in rare situations, when a load is ill-behaved or a board layout is poor or bypass capacitors are improperly selected-the output will oscillate. In a feedback loop, we’re always trying to balance the aggressiveness of the response (the speed that the regulator will respond to load changes) with stability over temperature, component variation, worst case circuit and device influences. This brings up subjects like Bode plots and phase/gain margin that are uncomfortable for some people.

So, when you look at designing with a part like the FAN21SV04 and see the external feedback loop components, we’re trying to do you a service. You can adjust the feedback compensation to meet the transient requirements of your design.  So I hope you agree - including a feedback loop will make your life easier.

Now if you’ll excuse me, I have to visit my therapist.


About the author:
Dr. Fred A. Engleberry (also know as Dr. F.A.E.) holds a PhD from MIT (Muckton Institute of Talknology). Fred has a world-class intellect and rarely neglects an opportunity to mention it. Argumentative and contentious, he's often irritatingly correct when answering questions and discussing semiconductor technology, real world design trade-offs and engineering issues. Dr. F.A.E's core competencies include using big words when small ones would suffice and providing long-winded, indirect answers to simple questions.

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Why did my FET fail?

August 25, 2009

- 3 Comments
By Dr. F.A.E.

We’re introducing a new blogger to the site: Dr. Fred A. Engleberry. Dr. F.A.E. holds a PhD from MIT (Muckton Institute of Talknology) and has several months of valuable experience with applied technology. We are pleased to have Dr. F.A.E. available to answer questions collected from customers around the world.

Dr. F.A.E, “Smoky” from General Specifics Inc. sent a question…”Why did my FET fail?” Without further ado, we’ll turn the session over to Dr. Fred.

First of all, Smoky, you’re probably expecting a lot of annoying questions about your design. Such as, what frequency you’re running at, what the gate drive circuit looks like, what the load is and what supply voltage is present. Some design engineers might try to determine whether there is an avalanche condition beyond what the device might be reasonably expected to tolerate, whether the gate drive is insufficient or oscillating, whether the load is inductive, whether voltage spikes creep too close to breakdown voltages on the gate or drain, or whether the total package dissipation is being exceeded.

However, let’s say in this instance I could see your schematic and Bill of Materials (BOM). Your gate resistor, R42, as noted on the schematic, should be one ohm, but the BOM shows 1,000 ohms. Replace this resistor with the proper value and you will find that your FET turn-on and turn-off rise and fall times will become reasonable and you will avoid gate oscillation – and your FET design will become robust.

Want more information on FETs? Check out our website for MOSFETs at http://fairchildsemi.com/products/mosfets/index.html


About the author:
Dr. Fred A. Engleberry (also know as Dr. F.A.E.) holds a PhD from MIT (Muckton Institute of Talknology). Fred has a world-class intellect and rarely neglects an opportunity to mention it. Argumentative and contentious, he's often irritatingly correct when answering questions and discussing semiconductor technology, real world design trade-offs and engineering issues. Dr. F.A.E's core competencies include using big words when small ones would suffice and providing long-winded, indirect answers to simple questions.

Tags: , , , ,

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